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A 50 -g sample of impure $\mathrm{KClO}_{3}$ (solubility $=7.1 \mathrm{g}$ per $\left.100 \mathrm{g} \mathrm{H}_{2} \mathrm{O} \text { at } 20^{\circ} \mathrm{C}\right)$ is contaminated with 10 percent of $\mathrm{KCl}$ (solubility $=25.5 \mathrm{g}$ per $100 \mathrm{g}$ of $\mathrm{H}_{2} \mathrm{O}$ at $\left.20^{\circ} \mathrm{C}\right) .$ Calculate the minimum quantity of $20^{\circ} \mathrm{C}$ water needed to dissolve all the KCI from the sample. How much $\mathrm{KClO}_{3}$ will be left after this treatment? (Assume that the solubilities are unaffected by the presence of the other compound.)

$$43.608 \mathrm{g}$$

Chemistry 102

Chapter 12

Physical Properties of Solutions

Solutions

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03:58

In chemistry, a solution is a homogeneous mixture composed of two or more substances. The term "solution" is also used to refer to the resultant mixture. The solution is usually a fluid. The particles of a solute are dispersed or dissolved in the solvent. The resulting solution is also called the solvent. The solvent is the continuous phase.

05:06

In physics and thermodynamics, the natural tendency of a system to change its state is its tendency to increase the entropy of the system. It is a measure of the disorder in a system.

04:35

A $50-\mathrm{g}$ sample o…

07:46

The Handbook of Chemistry…

10:08

The Handbook of Chemistry …

08:51

00:38

Use the following table.

06:50

The solubility of $\mathrm…

00:39

Okay, so we have a simple with 50 grams, okay? And we know the 5% of that is potassium chloride. So we have five grams off potassium. All right, because that's the contamination. Okay? And therefore, we have far 45 grams off potassium CLO rate. You okay? So the first step in this question will be to figure out how much water do we need to dissolve five grams off potassium chloride? Let's start five grams. Potassium chloride, and we have a data above the soy ability off that. Right. We know that with 100 grams of water, we can dissolve 25.5 grams of potassium chloride so we can include that here. So 100 grams of water it's necessary to dissolve 25.5. Grimm's off the potassium chlorate. Okay, so working this out, you find that the amount of water needed using this ratio is 20 Gramps. Okay, so we need 20 grams of water to dissolve five grams of potassium chloride. Okay, so let's move ahead. Now. We have the amount of water. The second step is to figure out OK if we use this amount of water to remove name purity. We also gonna dissolve some off the potassium chloride. Okay, that's in glory. The one with the options in the former. So we have to figure out how much off off the potassium chlorate will be left if we used that. This is a typical question off purifying a substance using differences and soluble ity. So let's go. So now we know that we're using 20 grams of water and we also have a soy ability off the port Tassan chlorine. And that is 70.1 grams off the potassium chlorine will dissolve in 100 grams of water. So we're asking ourselves if we know this, how much 20 grams of water will dissolve Another way to think about, like 20 just 100 divided by five. So you just think this number divide by five, right? This is a generally to work this out. So again, check your unit. If they make sense right, we get the mass off potassium chloride and there will be one point for Gramps of our our potassium chloride. Great. So that means there from the 45 grams we will have left. So we have left 43 0.6 grams okay. However, since the question has only two sick fix from the first data 50 grams, you would actually have to ride this as, um oops. You have to cut this six here cape and robbing that routing that up. You have 45 is your final insert respecting 66

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