00:02
In this problem, we're given a person of mass 50 kilograms varying high heels, and the radius of each heels is given to be 0 .5 centimeters.
00:24
And we need to find the pressure exerted when the person balances on one heel.
00:39
So first we can convert the radius into the si units of meters, and we can do that by multiplying by the preferect.
00:46
10 to the negative 2, which is the prefix for centi, and that just gives us 5 into 10 to the negative 3 meters as our answer for the radius in meters.
01:10
Now the pressure exerted is given by the formula force divided by area, and we need to calculate the area in contact with the heel and the ground.
01:25
So that's given by five times r squared, but r is the radius of the heel, and that just becomes five times five into 10 to the negative three, the whole squared, and this entire thing evaluates to 7 .85 into 10 to the negative 5 meters squared.
01:53
Now the force exerted is the weight of the person, and that is equal to the mass of the person times the gravitational acceleration.
02:06
The mass of the person is given to be 50 kilograms, and the gravitational acceleration g is 9 .8 meters per second squared...