Question
A $5.00-\mathrm{g}$ sample of one of the substances listed in Table $6.1$ was heated from $25.2^{\circ} \mathrm{C}$ to $55.1^{\circ} \mathrm{C}$, requiring $133 \mathrm{~J}$ to do so. What substance was it?
Step 1
We know that the heat transfer (Q) is 133 J, the mass (m) is 5 g, and the temperature change (ΔT) is 55.1°C - 25.2°C = 29.9°C. We can use the formula Q = mcΔT to find the specific heat capacity (c). Show more…
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