00:01
Okay, so the water and thermometer will eventually reach a thermal equilibrium, which will have q1 is equal to q2.
00:07
Q1 is the heat that was generated by the water during this process, and q2 is the heat that was generated by the thermometer during this process.
00:15
So if a negative m1, c1, t1, t1, t1, it's equal to m2, c2, t2, t33.
00:19
So t3 thermal is the equilibrium temperature, and t1i is the initial temperature for the water, which is the temperature we are looking for to determine.
00:28
And t2i is the initial temperature of a thermometer.
00:30
So if we do some arrangement here, we have t1i is equal to m2c2x2 -t thermal minus m2c210t thermal divided by m1c1c1.
00:42
So we know the mass of the thermometer is given as 50 grams.
00:45
If we convert to kilograms, it's 0 .05 kilograms.
00:49
In the specific heat for the thermometer is given as 50 jou per kilogram times kelvin, and thermal equilibrium temperature is 71 .2 degrees celsius.
00:57
If we convert to kelvin, it's 34 .2 kelvin.
01:01
And the initial temperature for the thermal meter is 20 degrees celsius, which is 293 kelvin.
01:08
The mass of water is equal to density water, tens of volume of water.
01:12
And we know the density water is 1 ,000 kilogram per meter cube.
01:15
And the volume is given as 200 millimeter.
01:17
If we convert to a meter cube, it's 2 times 10 -2 -8 -4 meter cube.
01:20
So eventually we have the mass of water is equal to 0 .2 kilogram.
01:24
And the specific heat for the water is 4190 per kilogram times kelvin.
01:28
So now we can determine the initial temperature, or the water, which is t1i, is equal to m2c2, which is 0 .05 kilogram times 750, jew per kilogram times kelvin, and n times, let me see, t thermal, which is 344 .0 .2 kelvin minus 0 .05 kilogram times 750 jew per kilogram...