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A 5.00 pF parallel-plate air-filled capacitor with circular plates is to be used in a circuit in which it will be subjected to potentials of up to $1.00 \times 10^{2} \mathrm{V}$ . The electric field between he plates is to be no greater than $1.00 \times 10^{4} \mathrm{N} / \mathrm{C} .$ As a budding electrical engineer for Live- Wire Electronics, your tasks are to (a) design the capacitor by finding what its physical dimensions and separation must be and (b) find the maximum charge these plates can hold.

(a) $r=4.24 \mathrm{cm}$(b) $Q=500 \mathrm{pC}$

Physics 101 Mechanics

Physics 102 Electricity and Magnetism

Chapter 18

Electric Potential and Capacitanc

Kinetic Energy

Potential Energy

Energy Conservation

Electric Charge and Electric Field

Gauss's Law

Electric Potential

Capacitance and Dielectrics

University of Michigan - Ann Arbor

University of Washington

Simon Fraser University

University of Winnipeg

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So is this question. We have a parallel plate, Capacitor said, is circular shaped and we do not know about the surface area and we do not know about the distance. But we knows the capacitors is because of capacitors is five pickle farrant and we know the voted across. It isthe 100 votes and we want the maximum electric field to be 1.0 times 10 to the force. You temper. Cool. Um, is this is a maximum. What? We do not want electric field to be any greater senses. So in part aid, it has justifies a time version of it. So to find a domination, a circular ship, parallel plate capacitance we have two sister find. One is what is the distance between them. And second is what is a radius of the plate. So to find the distance between them, this is a relatively easy one, because is that this turns between two places. Times of electric's electric field between the two plates equals a potential difference. So we have some potential difference and electric field. We can divide Cem to get the distance. So the equals one point there was zero times 10 to the second books and electric field is 1.0 times 10 to the Force, Utah's Brooklyn. So this gives us 1.0 times 10 to easy effective to yer, or 1.0 centimeter. So that is a separation between the two place. So sincerely what you find is a radius of plate, and this can be fine. Using equation 18 16. So Equation 18 16 has Kam passengers equals absolutely a already. So we have re arrange it so that we have find so surface area off the plates because we already find out what he is in the previous problem. Capacitance is five people. What I think of Ethical Parent Detective 12 Parent times one point 00 Cubs, 10 to Z objective to meter and divided by eight point. It's four times 10 to see a detective for off croup square times new 10 times meter square and this gives us a ulcer of 5.65 times 10 to Z inactive, same meter square. So that is a surface area. But the surface area equals pi r squared so we can find our by heavy r equals squared of a divide. A black eye equals crack 165 times and his elective three mere square find a nice 3.14 16 So this gives us 4.24 times stand his negativity. And Peter, which is 4.24 centimeter. So this is a radius. So we suppose the radius into separation. We can't design a we pretty much we have configured the whole shape of sis capacitors. The second question we need to answer is what is the maximum charge cease plays can hold. So the maximum church can be fine because we already have the capacitance. And when those uh voted setbacks, my voted across it. So Q is just to the passive tense times as a cottage. So the capacitance is 5.0 times 10 to the negative transparent turns 1.0 times 10 to the second votes said it's a total of 5.0 How's 10 to Z like pretend Coolum, which is 500 pickle coolers. So that is the maximum charge. This parallel plate care hold is a circuit

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