Question
A 50.0$\Omega$ resistor is connected as in Fig. $31-8$ to an ac generator with $8_{m}=30.0 \mathrm{V}$ . What is the amplitude of the resulting alternating current if the frequency of the emf is (a) 1.00 $\mathrm{kHz}$ and (b) 8.00 $\mathrm{kHz}$ ?
Step 1
The formula for Ohm's law is: \[I = \frac{V}{R}\] where: - \(I\) is the current, - \(V\) is the voltage, and - \(R\) is the resistance. Show more…
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A $50.0 \Omega$ resistor is connected as in Fig. $31-8$ to an ac generator with $\mathscr{E}_{m}=30.0 \mathrm{~V}$. What is the amplitude of the resulting alternating current if the frequency of the emf is (a) $1.00 \mathrm{kHz}$ and (b) $8.00 \mathrm{kHz}$ ?
A 50.0 $\mathrm{mH}$ inductor is connected as in Fig. $31-12$ to an ac generator with $\mathscr{E}_{m}=30.0 \mathrm{V}$ . What is the amplitude of the resulting alternating current if the frequency of the emf is (a) 1.00 $\mathrm{kHz}$ and (b) 8.00 $\mathrm{kHz}$ ?
Frequency of emf Is A $50 \Omega$ resistor is connected as to an ac generator with $\left|\mathscr{E}^{\max }\right|=30.0 \mathrm{~V}$. What is the amplitude of the resulting alternating current if the frequency of the $\mathrm{emf}$ is (a) $1.00 \mathrm{kHz}$ and (b) $8.00 \mathrm{kHz}$ ?
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