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A 5.012 -g sample of an iron chloride hydrate was dried in an oven. The mass of the anhydrous compound was 3.195 g. The compound was then dissolved in water and reacted with an excess of $\mathrm{AgNO}_{3} .$ The AgCl precipitate formed weighed 7.225 g. What is the formula of the original compound?

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The formula of the original compound is $\mathrm{FeCl}_{2} \cdot 4 \mathrm{H}_{2} \mathrm{O}$

Chemistry 102

Chapter 4

Reactions in Aqueous Solutions

Solutions

Aqueous Equilibria

Carleton College

University of Kentucky

Brown University

Lectures

03:58

In chemistry, a solution is a homogeneous mixture composed of two or more substances. The term "solution" is also used to refer to the resultant mixture. The solution is usually a fluid. The particles of a solute are dispersed or dissolved in the solvent. The resulting solution is also called the solvent. The solvent is the continuous phase.

00:41

In chemistry, an ion is an atom or molecule that has a non-zero net electric charge. The name was coined by John Dalton for ions in 1808, and later expanded to include molecules in 1834.

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A compound of iron and chl…

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A salt contains only bariu…

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03:46

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Okay for question 108: what do you 8 th? We have 5 what 55512 sambo and this sambo is dry after that we have. The mass 3 were 95 point: the mass removed us in the mass of water and then computist in water and react with silver nitrate and the silver clock at reception 2 to 5 gram. So, what's the formula of the original compound and now first we have to let the formula of iron law. So first we let them fall. Iron lawrahydrides is go f, e c s and water right after we dry it. We have so water right after we tries so we see the mass of the compound reduced. That means the water is evaporated, so mass of water, the mass before dry, minus mass after dry. Therefore we get and water we always so, and because we do the problem before under more radio, so we have for our polly 1. Okay, your part 111, and next we see we have to cover the maw of chivalrie devi form of the male massafai ma of silver, equally or 3, and now from the formula we see the molecule right you. What do we have here so get more chloris? That is what the masts will get the mass of it. We can calculate the mass of chloride in the compound iron bari, so we should have boy o 503 pi gram. So now we have in in the in 3.3 3.195 gram of the substance after after dry. It we have 1.7551 .784 gram chloride. So therefore, the mass 1.411 gram and we have a mass of lari where the mass of iron we can calculate the mass of them right now. Flora is equal. We have an claw equal. Let me see buoy 1784 r, divided by 35, pound 35.45 gram over more so this would be equal, oh no! We all right already. We call it above what i'm going to call it again. Now we only calculate a mass of iron, so we have n ion equals 1 boy, 411 gram, ironin and now we see the rate of okay and in more iron of a macluride equal po o 252 simon divided by boy, o fie, o dosia, righto boy, o 5, o 35. In you formula we have f a c l as time and water so hot over as i go the map iron over the prize. So we have here, it goes 1 half and now we'll end up. In 11, over n equals po o 252 sigma. An ego boy want money, .1 or 1 more for 01001 point, so this equals 1 for poore the formula. Now we substitute the data here in the formula, so we have the formula should be f a c l. 4, water.

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