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A $525-\Omega$ resistor and a $295-\mathrm{mH}$ inductor are connected in series with an ac generator with an rms voltage of 20.0 $\mathrm{V}$ and a frequencyof 60.0 $\mathrm{Hz}$ . What is the rms current in this circuit?

$= 37.3 \mathrm{mA}$

Physics 102 Electricity and Magnetism

Chapter 24

Alternating-Current Circuits

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Electromagnetic Induction

Alternating Current

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the relation between the aromas, voltage and the Aramis current is the following. The IRA man's voltage is he goes to the Ari Mass. Current times impudence. And in the situation, the impedance has two contributions. Contribution coming from the resister, which is R squared, and another contribution coming from the doctor, which is two pi frequents times in luck tints squared. Then we can solve this equation for the current to get i r. A mass is equals two. The square root off our square plus to buy f l squared This is all under the voltage the your mess Now we can plug in the values given by the problem to get ah, you're a mess is equals two the square root off 5 25 squared Plus to buy times the frequency 60 time thing Look tense 295 merely Henry squared and this is all under the voltage which is equal to 20. And finally this is approximately 0.37 to 6, which can be written as 37.3. I really am Piers

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