Question
A $540-\mathrm{W}$ electric heater is designed to operate from 120 $\mathrm{V}$ lines. (a) What is its resistance? (b) What current does it draw? (c) If the line voltage drops to $110 \mathrm{V},$ what power does the heater take? (Assume that the resistance is constant. Actually, it will change because of the change in temperature.) (d) The heater coils are metallic, so that the resistance of the heater decreases with decreasing temperature. If the change of resistance with temperature is taken into account, will the electrical power consumed by the heater be larger or smaller than what you calculated in part (c)? Explain.
Step 1
We can use the formula for power, which is $P = V^2/R$, where $P$ is power, $V$ is voltage, and $R$ is resistance. We can rearrange this formula to solve for resistance, giving us $R = V^2/P$. Show more…
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A "540-W" electric heater is designed to operate from 120-V lines. (a) What is its resistance? (b) What current does it draw? (c) If the line voltage drops to 110 V, what power does the heater take? (Assume that the resistance is constant. Actually, it will change because of the change in temperature.) (d) The heater coils are metallic, so that the resistance of the heater decreases with decreasing temperature. If the change of resistance with temperature is taken into account, will the electrical power consumed by the heater be larger or smaller than what you calculated in part (c)? Explain.
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