A 60 kg JATAN with 10 kg load on his head climbs 25 steps of 0.20 m height each. What is the

Name: Problem 421, Chapter 4: JEE Physics
Uploaded: 2021-10-01T20:17:05-08:00
Duration: 1 min 46 s
Channel: Narendra Kumar
Description: A 60 kg JATAN with 10 kg load on his head climbs 25 steps of 0.20 m height each. What is the work done in climbing ? (g=10 m / s^2) (A) 5 J (B) 350 J (C) 100 J (D) 3500 J

step 1 Here we have given a 60 kj Jatin with 10 kg load on his head claims 25 steps of 0 .20 meter heig

Question

A $60 \mathrm{~kg}$ JATAN with $10 \mathrm{~kg}$ load on his head climbs 25 steps of $0.20 \mathrm{~m}$ height each. What is the work done in climbing ? $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)$ (A) $5 \mathrm{~J}$ (B) $350 \mathrm{~J}$ (C) $100 \mathrm{~J}$ (D) $3500 \mathrm{~J}$

   A $60 \mathrm{~kg}$ JATAN with $10 \mathrm{~kg}$ load on his head climbs 25 steps of $0.20 \mathrm{~m}$ height each. What is the work done in climbing ? $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)$
(A) $5 \mathrm{~J}$
(B) $350 \mathrm{~J}$
(C) $100 \mathrm{~J}$
(D) $3500 \mathrm{~J}$

JEE Physics

StemEZ 1st Edition

Chapter 4, Problem 421

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Solved by Expert Narendra Kumar

10/01/2021

Step 1

This can be done by multiplying the number of steps climbed by the height of each step. So, the total displacement $d$ is given by: \[d = 25 \times 0.20 = 5 \, \text{m}\] Show more…

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A $60 \mathrm{~kg}$ JATAN with $10 \mathrm{~kg}$ load on his head climbs 25 steps of $0.20 \mathrm{~m}$ height each. What is the work done in climbing ? $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)$ (A) $5 \mathrm{~J}$ (B) $350 \mathrm{~J}$ (C) $100 \mathrm{~J}$ (D) $3500 \mathrm{~J}$

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Key Concepts

Mechanical Work

Mechanical work is the energy transferred when a force is applied to move an object over a distance. In physics, it is defined as the product of the force component in the direction of displacement and the magnitude of the displacement.

Gravitational Potential Energy

Gravitational potential energy represents the energy stored in an object due to its position in a gravitational field. It is calculated by multiplying the object's mass, the acceleration due to gravity, and the height gained, which quantifies the work done against the force of gravity.

Acceleration Due to Gravity

Acceleration due to gravity is the constant rate at which objects accelerate towards Earth under the influence of gravity. It is a crucial factor in calculating gravitational potential energy and mechanical work when moving objects in a gravitational field.

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