00 mA and the resistances $R_{1}, R_{2},$ and $R_{3}$ are in series. So we can write the total resistance as $R_{1} + R_{2} + R_{3}$. Using Ohm's law, we can find the total resistance as $V/I = 6.00 \, \text{V} / 1.00 \, \text{mA} = 6.00 \times 10^{3} \, \Omega$.
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