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A 65 -kg hiker climbs to the top of a 4200 -m-high mountain. The climb is made in 5.0 h starting at an elevation of 2800 m. Calculate $(a)$ the work done by the hiker againstgravity, $(b)$ the average power output in watts and in horsepower, and $(c)$ assuming the body is 15$\%$ efficient, what rate of energy input was required.

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A) $8.9 \times 10^{5} \mathrm{J}$B) $5.0 \times 10^{1} \mathrm{W}$ $66 \times 10^{-2} \mathrm{hn}$C) 330$W$ 0.44$h p$

Physics 101 Mechanics

Chapter 8

Conservation of Energy

Work

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

Cornell University

Rutgers, The State University of New Jersey

McMaster University

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

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So that is a mountaineer who is going climbing mountain and is going against gravity. And in this question, we need to actually calculate he's climbing to a 4200 mountain here, and he takes an average of five hours, starting a little elevation off 2800. So the first part of the question is, what is the work done? So work done by gravity basically is equals. Two mg change off height, so that equals 2 65 times 9.8 times The change of height is 4200 minus 2800. So that is approximately 8.9 times turned to the park off. Five. Jules. So that is the work done, and the part output in Watts Bar is equals two. The world done by gravity, divided by time. So that is 8.9 times tend to the part off five divided by five hours. Convert that two seconds, which is like 3600 seconds, should give you 49.54 words par. Region rates Nobody to convert that to horse far, so we'll divide 49.5 by 7 46 works because my heart spot is 74 to 6 parts, so that does six points six times. Turn to the par negative to horse bar. And then if his body is 15% efficient, what is the energy output? So power output equals 0.15 which is 15% times far input. So that equals 2 49.54 divided by sorry. We need to cooperate. Power input. So part input is equals. Two power output divided by 20.1 fight so that ISS 49.5, divided by 0.15 equals 3 30 works. Well, that is approximately equals 2.44 horse far.

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