Like

Report

A $65.0 \mathrm{kg}$ ice skater moving to the right with a velocity of $2.50 \mathrm{m} / \mathrm{s}$ throws a $0.150 \mathrm{kg}$ snowball to the right with a velocity of $32.0 \mathrm{m} / \mathrm{s}$ relative to the ground.

a. What is the velocity of the ice skater after throwing the snowball? Disregard the friction between the skates and the ice.

b. A second skater initially at rest with a mass of $60.0 \mathrm{kg}$ catches the snowball. What is the velocity of the second skater after catching the snowball in a perfectly inelastic collision?

a. $v_{1, f}=2.43 \mathrm{m} / \mathrm{s}$

b. $v_{f}=0.08 \mathrm{m} / \mathrm{s}$

You must be signed in to discuss.

Cornell University

University of Washington

Simon Fraser University

Hope College

side Ready Scitex and Liberty to write out some things for us. For this problem, we have a mass of a skater of the problem. A 65 kilograms. The velocity is 2.5 whose per second, 0.150 kilograms for the snowball and a velocity of 32 meters per second. So for this we're gonna do the first part and we end up with We're gonna take the 2.5 meters per second out and we're gonna add 65 kilograms plus 0.15 kilogram. And we're also gonna have equal to 65 kilograms times the velocity. We're trying to find claws. There you go, Eric. I want choice, please. Everything in? Yes, on What we're gonna be doing is just solving it. The math here for you guys. So let me just put everything in my calculator here. I mean, up with one 65 0.875 kilograms Meters, four seconds. I'm sorry. My s is help, like five sometimes there we go. Minus it. Would a minus this right here for us because, um, he keeps things a little bit more. Ah, simple. When we do that so minus 4.8 kilograms. I'm not sure what I did to get that giant liner here, but it's open, and we're gonna McKnight ass a little bit better for you guys. There we go. Unless equals 65 kilogram philosophy. And I'm just gonna do this really quick. Actually, this is 62. I don't know why I wrote that wrong. Even though I have my calculator at year. But it's okay. We caught it. And what was gonna dio is 1 58 0.0 75 divided by 65 kilograms. And these kilograms, we're all gonna council out. Yeah, and we know with Silver Second, and that's gonna be our velocity here. And that's gonna equal point for three meters per second. And that's hard to answer now. Uh, a second suitor on the second skater is mass is a kilogram, and the missile is a hero. And because of that, we are having 60 right here. I would have the snowball first on the left hand side of the place and that we did above So having 0.1 by Phil Gramm of a snowball Heinz 32 years per second. Now that's gonna be equaling you. And we have a B F A final and yet six waas massive the I wanna put kilograms. Yes, You guys know that I'm not forgetting that now you can just simply multiply things together. So get 4.8. You're kilograms, meters seconds because the and this is gonna be 60 0.15 gram and kilograms canceled. And our answer is good be when we divide 0.1 7 98 with is your 0.8 second and this is our second answer.

Oakland University