Question
A ${ }^7 \mathrm{~N}_{14}$ nucleus has nuclear spin $I=1$. Assume that the diatomic molecule $\mathrm{N}_2$ can rotate but does not vibrate at ordinary temperatures and ignore electronic motion. Find the relative abundances of the ortho- and para-molecules in a sample of nitrogen gas. (Ortho $=$ symmetric spin state; Para $=$ antisymmetric spin state). What happens to the relative abundance as the temperature is lowered towards absolute zero? (Justify your answers!)
Step 1
The nitrogen nucleus \({ }^7 \mathrm{~N}_{14}\) has a nuclear spin \(I=1\). This means it can have three possible magnetic quantum states: \(m_I = -1, 0, +1\). Show more…
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Suppose one wished to maintain a population inversion between the ground (1s22s22p3) and 4D3/2 excited states of atomic nitrogen by simple heating. The term value for the 4D3/2 state is 19244 cm-1. What temperature would be necessary to maintain double the number of N atoms in the excited state, relative to the ground state? What is the significance of the result you obtain? (Hint: Nu/Nl= (2J+1)u/(2J+1)l e^(-ΔE/kT)) What is alpha in your answer?
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