00:01
So this is essentially a free fall problem.
00:02
We can use kinematics for free fall problems.
00:06
However, we're going to use the conservation of energy.
00:09
And again, we can say that the initial potential energy would be equal to the final kinetic energy.
00:14
This would be equal to m, g, y initial.
00:17
This would equal one half mv squared.
00:21
Masses of course cancel out.
00:23
So v will be equal to 2gy initial.
00:27
This is equaling the square root of 2 times 9 .8 meters per second squared times the height with which it falls.
00:38
So 4 .3 meters and the velocity is then equaling 9 .2 meters per second.
00:47
This would be our final answer for part a.
00:51
Now for part b, we know that the change in thermal energy is going to be, equal to the kinetic force of friction times the distance or the work of friction...