00:01
From the graph a point to the dynamic viscosity, mu of s -a -e -10w, oil at 25 degrees centigrade, can be written as mu is equal to 0 .13 newton second per meter square.
00:16
Now the density of aluminum piston can be found by using formula as z -a -l is equal to ro -o -almunium divided by row water.
00:29
So from this equation we can find ro aluminum is equal to as z multiplied by row h2 or we can find ro aluminum is equal to as z of o as z can be retained as 2 .6 2 .64 multiplied by row of water is thousand so from this density of aluminum aluminum is equal to 2640 2640 kg per meter cube.
01:06
Now we will calculate the mass of aluminium piston.
01:08
Mass of aluminium piston can be found by using formula m aluminium is equals to row aluminium multiplied by v piston.
01:24
So row aluminium multiplied by velocity of piston can be written as pi by 4.
01:32
Multiplied by l.
01:34
So we will put the values of all the variables and we can find the value of mass of aluminum.
01:41
2640 multiplied by pi by 4 multiplied by 73 into 10 to the power of minus 2 whole square multiplied by length is equal to 0 .1.
01:54
So the mass of the aluminum will come out to be 1 .1044 kg...