Question
A $75-\mathrm{kg}$ person is exposed to 45 mrem of $\alpha$ particles $(\mathrm{RBE}=12) .$ How much energy has this person absorbed?
Step 1
E.D). The formula for B.E.D is given by: \[ B.E.D = A.D \times R.B.E \] where A.D is the absorbed dose and R.B.E is the relative biological effectiveness. Show more…
Show all steps
Your feedback will help us improve your experience
Narayan Hari and 83 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A $75-\mathrm{kg}$ person is exposed to 45 mrem of $\alpha$ particles $(\mathrm{RBE}=12)$ How much energy (in joules) has this person absorbed?
A person whose mass is $75 \mathrm{kg}$ is exposed to a dose of 25 rad. How many joules of energy are deposited in the person's bodv?
A 75 kg person receives a whole-body radiation dose of 2.4 * 10-4 Gy, delivered by alpha particles for which the RBE factor is 12. Calculate (a) the absorbed energy in joules and the dose equivalent in (b) sieverts and (c) rem.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD