A 75.0 -kg person is standing on a scale in an elevator....

A 75.0 -kg person is standing on a scale in an elevator. What is the reading of the scale in newtons if the elevator is (a) at rest, (b) moving up at a constant velocity of $2.00 \mathrm{~m} / \mathrm{s},$ and $(\mathrm{c})$ accelerating up at $2.00 \mathrm{~m} / \mathrm{s}^{2} ?$

Key Concepts

Apparent Weight

Apparent weight is the weight an object seems to have when measured by a scale, which is the result of the normal force acting on it. This can differ from the true gravitational weight when additional acceleration (such as from an elevator starting or stopping) is present, causing the reading to increase or decrease accordingly.

Acceleration Effects in Non-inertial Frames

When an object is in a non-inertial frame, such as an accelerating elevator, additional forces (or effective forces) act on it. This means that the object's apparent weight can change compared to its weight under stationary conditions, requiring the inclusion of the elevator's acceleration in force calculations.

Newton's Second Law

This law states that the net force on an object is equal to the mass of the object multiplied by its acceleration. It is essential for analyzing forces in systems that are either in equilibrium or accelerating, such as an elevator, and allows for the calculation of the net force based on the acceleration experienced by the object.

Normal Force

The normal force is the support force exerted by a surface perpendicular to the object in contact with it. In the case of a person standing on a scale in an elevator, the reading on the scale corresponds to the normal force, which can vary when the elevator accelerates even if the gravitational force remains constant.

Transcript

Please give Ace some feedback