Question
A $75.0$ -kW, 230 - $V$ shunt generator has a generated emf of $243.5$ $\mathrm{V}$. If the field current is $12.5 \mathrm{~A}$ at rated output, what is the armature resistance?
Step 1
We can use the formula $I = \frac{P}{V}$, where $P$ is the power and $V$ is the terminal voltage. Substituting the given values, we get: \[I = \frac{75000}{230} = 326.087 \, \text{A}\] Show more…
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