00:01
Okay, so for this question, the first thing that we can do is calculate the change in temperature.
00:06
So, delta t is equal to the t final minus t initial, right? so we have t final is zero degrees celsius.
00:14
We got to convert that to kelvin's 273 .15 kelvin per degree celsius, minus the t initial, right? so we have 98 .6 degrees celsius plus 273 .15 kelvin.
00:30
For celsius, right? the celsius cancels out and we're left with kelvin on both sides.
00:36
And we get delta t to be equal to negative 98 .6 kelvin.
00:42
Now, the question they tell us that 0 .37 grams of ice melted.
00:46
We can calculate how much energy q is needed to melt 0 .37 grams of ice.
00:53
Right, the equation is q is equal to m mass times by heat of fusion, right? because we're doing, we're melting.
01:01
The ice.
01:03
So m is 0 .37 grams and the hf or the heat of fusion of ice is 333 joules per gram.
01:17
Right.
01:18
So grams cancels out we're left with jewels and that is the units for q.
01:23
The answer is 1 .23 times 10 to the 2 joules...