00:01
30 .78.
00:03
Imagine we have a couple samples of natural carbon that contains the usual fraction of carbon 14.
00:10
So we want to estimate about how long it takes until each one of them contains only one carbon 14 nucleus.
00:21
So from section 30 -11, the usual fraction of carbon 14 is 1 .1.
00:38
Three times 10 to the negative 12.
00:44
So not a whole lot.
00:46
Because this is very small, we're just going to use the atomic weight of carbon 12 to find the number of carbon atoms in 72 grams because you know, it's going to get lost in the noise if you try and use this anyway.
01:04
You'd need way more digits than just two basically in order for that to be meaningful.
01:13
So then the number of carbons is going to be 72 grams of the sample divided by 12 grams per mole times avagadro's number and so this is going to be 3 .612 times 10 to the 24th atoms so the number of carbon 14s will have to begin with is 4 .612 times 4.
02:15
4 .7 times 10 to the 12.
02:25
So you see 12 word is a magnitude less as you'd expect.
02:34
So then using the n equals n0 e to the negative lambda t, you know, thing we've been using all chapter.
02:57
Just go right ahead and write down an expression for the time this will take...