00:01
In this problem, we have a conducting loop in the shape of a square with given edge length, and we want to calculate the magnitude and direction of the magnetic field at the center of that square.
00:10
We then want to find what would happen if this conductor was reshaped to be a circular loop and carry the same current.
00:16
So in the first case, we know that we can rewrite our typical equation for b if we are working at a point that is a certain distance from our current carrying wire.
00:25
In this case, our b is not equal to mu not i over 2 pi r, but equal to mu not i over a 4.
00:31
4 pi r times sine of theta i plus sine of theta 2.
00:34
And our thetas are labeled in this diagram over here.
00:38
Now in this problem, we are given that the length of 100 of the square is 0 .4 meters and the current is 10 a peers.
00:46
So, and we're also given the fact that since this is a square, all of our thetas must be equal to 45 degrees.
00:53
Furthermore, since we're finding the curve, this is furthermore, since we're finding the magnitude direction of the field at a, at a, at the other corner of the square, and we know that a diagonal of a square is its length divided by 2, we also have a, our radius.
01:09
Now, we can plug in all the quantities that we need to solve our problem, which we find then is equal to the square root of 2 times mu not times i divided by 2 pi l, or l is the length of one side of our square.
01:22
We also find, using the right hand rule, which you can visualize on your own, that the field must be pointing into the page.
01:29
Now, a square has four sides, obviously, so our magnetic field isn't just coming from one of them...