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A A flywheel having constant angular acceleration requires4.00 s to rotate through 162 rad. Its angular velocity at the endof this time is 108 rad/s. Find (a) the angular velocity at thebeginning of the 4.00 s interval; (b) the angular acceleration ofthe flywheel.

a) $-27 \mathrm{rad} / \mathrm{s}$b) 33.75 $\mathrm{rad} / \mathrm{s}^{2}$

Physics 101 Mechanics

Chapter 9

Rotational Motion

Physics Basics

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Sheekshya N.

October 28, 2020

Cornell University

Hope College

University of Sheffield

Lectures

04:16

In mathematics, a proof is…

04:48

In mathematics, algebra is…

02:40

During a 6.0-s time interv…

03:29

A flywheel has angular acc…

05:45

A flywheel slows from 600 …

01:57

The flywheel of an engine …

03:48

ILW A flywheel turns throu…

04:08

A flywheel with a radius o…

04:38

$\bullet$ A flywheel with …

02:21

A wheel starts from rest a…

03:17

A wheel has a constant ang…

00:39

00:45

A turntable rotates with a…

02:07

$\because$ The rotor in a …

01:04

03:32

A wheel, starting from res…

03:24

The angular velocity of a …

02:03

$\cdot$ A wheel turns with…

02:58

The motion of an oscillati…

02:49

A rotating wheel requires …

03:23

A wheel of diameter 40.0 c…

04:40

CP CALC The angular veloci…

Let's use the rotational cinematic equations. Help us solve this problem. The time of the process is four seconds. The angle traveled. They did. My stay or not is equal to 162 Radiance. The final angular velocity is 108 radiance a second and our desired unknown is the initial your velocity. To do this, we're going to use this cinematic equation. They don't mind stated on Siegel to omega Non puzzle Megha over two times the time solving this for Omega not gives omega non equals to fade him. Want to stay the night over tea minus omega, which eagles negative 27. Praise for second. Whenever you plug in all of these values over here and that's the answer to party, Barbie is asking for the angular acceleration. And so, for this we can use Omega is equal to Omega night, plus Alfa Time, Steve solving for Alfa Omega by something and I over tea. And then we can just plug in these which we found on the previous page or were given to us originally. Yeah, so you get 100 eh? Minus native 27. This is what we found in party over four seconds and that equals 33 0.75 radiance per second squared, and that's the final answer to problem.

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