00:01
Okay, a sample of hydrogen gas is generated in a closed container.
00:25
The reaction has 1 .750 grams of zinc reacting with 50 .0 milliliters of 1 .00 molar of hydrochloric acid.
00:45
We're going to write the balanced chemical equation and calculate the number of moles of hydrogen formed.
00:53
Balanced equation, moles of h2 formed.
01:09
First, our balanced chemical equation, zinc reacts with hydrochloric acid to produce zinc chloride and hydrogen gas.
01:28
We'll balance the equation as follows.
01:32
Now we're going to do a simple limiting reactant problem, and first we're going to calculate moles of both of our reactants.
01:42
Let's switch colors.
01:46
Calculate moles of zinc, we're going to take our mass of zinc, multiply by the molar mass of zinc, which i wrote down a moment ago, 65 .390.
02:06
0 .02676 moles of zinc.
02:14
Second, let's calculate our moles of hydrochloric acid.
02:25
That will equal our volume in this volume in liters, multiplied by the molarity.
02:54
Next, we're going to do our limiting reactant, and i'm going to cheat a little bit, and do a mole box.
03:04
We have my coefficients, how many moles i have, how many moles i need, and how many moles of excess.
03:19
I think we have hcl, my coefficients are 1 and 2.
03:31
Moles that we have, we're calculated as, let me raise some of this, and 0 .0500.
03:49
To find the number that goes right here, i take this times 1 divided by 2, and this gives me 0 .00126.
04:09
26, i believe.
04:16
Is that a 7 ?176.
04:48
And i find the number that goes right here.
04:52
Take this number times divide.
04:55
This is 0 .05320.
05:02
So this is my limiting.
05:05
The hcl is my limiting reactor.
05:07
So i'm going to use my hydrochloric acid moles and my mole ratio of 2 to 1 to come up with 0 .02 .2.
05:39
5 .0 moles of h2.
05:45
This is how many moles of h2 are produced.
05:54
Part b says the volume over the solution in the container is 150 milliliters...