Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

(a) A shirtless rider under a circus tent feels the heat radiating from the sunlit portion of the tent. Calculate the temperature of the tent canvas based on the following information: The shirtless rider’s skin temperature is $34.0^{\circ}{C}$ and has an emissivity of $0.970 .$ The exposed area of skin is 0.400 ${m}^{2}$. He receives radiation at the rate of 20.0 W—half what you would calculate if the entire region behind him was hot. The rest of the surroundings are at $34.0^{\circ} {C}$ . (b) Discuss how this situation would change if the sunlit side of the tent was nearly pure white and if the rider was covered by a white tunic.

Part $(a) : \mathrm{K.E}=3 \times 10^{17} \mathrm{J}$Part $(\mathrm{b}) : \mathrm{m}=10^{13} \mathrm{kg}$Part $(\mathrm{c}) :$ thermal energy will raise the ocean's temperature and kinetic energy will disturb the water causing waves.

Physics 101 Mechanics

Chapter 14

Heat and Heat Transfer Methods

Thermal Properties of Matter

Rutgers, The State University of New Jersey

Hope College

University of Sheffield

McMaster University

Lectures

02:20

A solid, liquid, or gas is…

06:13

Matter is a state of aggre…

12:15

An astronaut performing an…

04:23

A student is trying to dec…

03:22

A hiker is wearing wool cl…

01:21

The surface area of an unc…

03:13

02:25

(a) Calculate the rate at …

02:55

The thermal conductivities…

01:48

A person is standing outdo…

02:12

02:14

Find the net rate of heat …

03:29

Suppose you walk into a sa…

05:38

A person who has skin of s…

02:58

A person with skin of surf…

03:37

The basal metabolic rate i…

04:13

Overall, 80$\%$ of the ene…

02:52

A person of surface area $…

04:40

Consider a poor lost soul …

06:33

Radiation by the body. The…

02:43

A mountain climber wears a…

06:47

A leaf of area 40 $\mathrm…

the center for this question is to look at how hideous being conducted through the space suit right off astronaut, out to a patch and then off into space. No, the two different, um, transfers or heat right method of transfer heat that we are discussing over here. The first would be via conduction, right? We have the suit ready. Astronauts having a temperature off about 20 degrees Celsius, that is insight, this suit. And then this amount of heat is transferred over to the patch right through the signals off the suit via conduction. For the second part of this question, is the patch itself transferring heat too? The space. Now the issue of that is that Ah, space itself is considered to be kind of like a vacuum. So there's very little air molecules that is around to conduct heat away. So this vacuum over here So there is very little conduction, all right, mostly the heat will be lost. True radiation. So radiation, it will be the main source off heat transfer from the patch to the environment. So what determines the rate at which Depeche he meets this radiation? Well, there's see Stepha Bozeman's Equation three p equals two e. M s sensitivity times the staffer Bozeman's constant times the AEA times the temperature to the power fall. All right, so, uh, the vacuum itself, right, because its temperature off the vacuum is cereal Calvin's. So we do not expect it to actually absorb any radiation from the surroundings. Right? So the incoming radiation using the same equation with t equals to zero will be just zero. So there's no incoming radiation that will need to be aware off. So now let us start off 50 conduction part. This conduction part would actually determine what is the inner What is the temperature off our patch? Right, Because by conduction, you know that the rates off heat transfer be given a the summer conductivity multiply by the area multiplied by the difference in temperature. Can I assume that the temperature is smaller than 20 degrees? So we have t minus sorry 20 minus t divided by the thickness off the space suit. Now I assume that he patches almost Ah, infinitely teen, right such that it only has one temperature now with this amount off energy that is being transferred from the astronomer itself to the patch you expect that thermal equilibrium. This will also be equal to the amount off radiation there is being emitted right by our pitch. So this is he goes to e time Sigma a teachable four developed by Sorry rates. So though, if this equation we are ready to soft Transall for this So 40 So we carry off a is the common factor and then we try to bring all the term with tea to one side, or we don't have to do that, actually, because this is quite difficult to solve energetically. So I want to do is, uh that are substituting the values for us. So t, uh, in this equation over here has to be in terms off Kelvin's, right? So we're gonna convert this into Kelvin's. So 20 degrees would be 20 plus 2 273.15 is, uh, to 93.15 Calvin's NST the Dominican activity case, given as you 0.6 and the sickness yah in terms off site units meters is your points yours your five meters with this too. In Mississippi? Yeah, just given us. Ah, point tree times The sportsmen, Stephan Weizman's constant. Here is 5.67 I am standing on my feet. So in order to solve for this equation, we could use a graphing calculator. We got a plot to graphs. One of it ISS first graph of why goes to 1.7 hosted prominent eats extra power four and then the other equation me Why it goes to point your six right by point. Here's your five chop off. All right, so this is the creation. So just a rough sketch, right? We expect something like, Ah, this is a extra powerful graph. They centered around white goes to Sorry. Exa goes to zero. So should be something like this. Where is the Avakov? Over here is a negatively sloped linear cuff. All right. And when exit goes to zero, you get a positive value. Right? So this is rest. This is why it goes to 1 47. Alright. What we're interested in is through the intercepts right where these two equations are equal to each other now, of course, our X is actually our temperature. And that is what we want to find o. T. So this would be your answer R t in terms off the Calvin's skill cannot be. Zero cannot be under zero. Cannot be negative. So we can ignore this solution. We're here. You can just ignore and focus only on the positive solution. A dis positive solution over here should be about 283.8. All right, so this implies that's the temperature. Must be to a tree for it. Kill fits. Now you want to determine what is the rate off heat lost. Body pitch. Right. So which is our equation over here? This is the equation. Great. Off heat loss, Miss Activity Times Stepha Bushman's constant times. The area times temperature about four. So the patches given us five times a C m. So that's your 50.5 m times your points. You will eat. It'll be multiplied by the temperature to a 3.8 to power four. This should give us about your point for for one. What's

View More Answers From This Book

Find Another Textbook

A solid, liquid, or gas is one of the three main states of matter. Solids ha…

Matter is a state of aggregation for a collection of atoms, molecules, ions,…

01:46

Unreasonable Results(a) What is the internal resistance of a 1.54-V dry …

02:17

What is the back emf of a 120 V motor that draws 8.00 A at its normal speed …

02:11

(a) A car generator turns at 400 rpm when the engine is idling. Its 300 -tur…

11:07

A multipurpose transformer has a secondary coil with several points at which…

01:34

What power is supplied to the starter motor of a large truck that draws 250 …

03:05

In the August 1992 space shuttle flight, only 250 $\mathrm{mot}$ of the cond…

04:39

(a) Find the size of the smallest detail observable in human tissue with 20.…

00:39

Calculate the voltage applied to a 2.00$\mu \mathrm{F}$ capacitor when it ho…

01:47

(a) Using information in Figure $25.52,$ find the height of the instructor&#…

10:03

A large research solenoid has a self-inductance of 25.0 H. (a) What induced …