00:01
So we can say for part a, first three seconds, we have that the maximum velocity is equaling the initial velocity, which we know to be zero at the beginning.
00:18
This would be plus the maximum acceleration times t of 3 .00 seconds.
00:24
And so the maximum velocity would be equaling 3 .00 times the maximum acceleration.
00:30
Now, the distance traveled within those three seconds, we can say x sub 1.
00:36
This would be equal to one half times the maximum acceleration times 3 .00 seconds squared.
00:45
And so this would be equalling one half times the maximum velocity divided by three multiplied by nine.
00:56
And this is equaling 1 .50 times the maximum velocity.
01:01
Now, because in the next 6 .69 seconds, bolt did not accelerate, so we can say x sub 2 is simply equalling 6 .69 times the maximum velocity, since he keeps this velocity for the next 6 .69 seconds.
01:19
We know that the total distance x sub 1 plus x sub 2 should equal 100 meters, because it's a 100 meter dash, and this is equal 1 .5 maximum.
01:32
1 .50 times the velocity max, multiplied by 6 .69 times a velocity max.
01:38
And so this would be equaling 7, so 8 .19 times the maximum velocity.
01:48
And so to solve for the maximum velocity, this would be 100 divided by 8 .19, 12 .2 meters per second.
01:58
And so the maximum acceleration is equaling 12 .2 meters per second divided by three, and this is equaling 4 .07 meters per second squared.
02:12
This would be our final answer for the maximum acceleration during those first three seconds.
02:17
That would be our answer for part a.
02:20
For part b, we have that here...