Question
(a) According to a report in the Roanoke Times \& World-News, approximately $2 / 3$ of the 1600 adults polled by telephone said they think the space shuttle program is a good investment for the country. Find a $95 \%$ confidence interval for the proportion of American adults who think the space shuttle program is a good investment for the country.(b) What can we assert with $95 \%$ confidence about the possible size of our error if we estimate the proportion of American adults who think the space shuttle program is a good investment to be $2 / 3 ?$
Step 1
In this case, the number of successes is $2/3$ of 1600, which is approximately 1067. So, the sample proportion is $p̂ = 1067/1600 = 0.667$. Show more…
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(a) According to a report in the Roanoke Times, approximately $2 / 3$ of 1600 adults polled by telephone said they think the space shuttle program is a good investment for the country. Find a $95 \%$ confidence interval for the proportion of American adults who think the space shuttle program is a good investment for the country. (b) What can we assert with $95 \%$ confidence about the possible size of our error if we estimate the proportion of American adults who think the space shuttle program is a good investment to be $2 / 3 ?$
One- and Two-Sample Estimation Problems
Two Samples: Estimating the Difference between Two Proportions
A recent Gallup poll asked Americans whether they thought that NASA's space program had brought enough benefits to justify the cost. Based on a telephone survey with 1,018 respondents, they found that 58% responded yes. a) Construct a 95% confidence interval for the true proportion of Americans who feel that NASA's space program had brought enough benefits to justify its cost. b) Suppose we wished to construct a 95% confidence interval with a width of 0.02 (that is, 2%). What sample size would we need?
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