00:02
So once again, welcome to a new problem.
00:05
We're dealing with a new selection.
00:07
And a lot of people have love for radio stations.
00:12
You know, radio goes way back where based on specific frequencies, people can listen to their favorite musicians or favorite broadcasters.
00:25
And so if you think about an fm radio station, that's a specific frequency that you're dealing with.
00:35
And the frequency you're dealing with in this instance is 101 .3 megahats.
00:45
So there's broadcasting going on.
00:48
We still have waves that are needed to broadcast from one location to the other one.
00:57
So if you're listening to your radio station, your favorite radio station, the reason the reason why that's happening is because you've tuned into a specific frequency.
01:09
So this is an fm broadcasting.
01:12
We have 1 .1 .3 megahats.
01:16
Sometimes you hear, they say, oh, 101 .3 the beat or something like that.
01:22
So we want to find the wavelength that's connected to this frequency.
01:28
That's the first part of the problem we're dealing with.
01:31
So we're going to go ahead and see that if we have a a frequency of 1 .1 .3 megahertz, we can change that to hearts and that's because 10 to the 6 hearts is the same as 1 mega heart.
01:59
And so f becomes 101 .3 times 10 to the 6 hearts.
02:06
That's what we're dealing with right there.
02:09
And then we move ahead and see, that since the signal for the radio station, it's electromagnetic signal, it's going to have a velocity c which is 10 to the 8 times, 10 to the 8 meters per second.
02:34
That's the velocity would give me.
02:36
So if v is f lambda and we wanted to find lambda, we'd have to divide both sides by the frequency.
02:44
And so our lambda for the fn radio station is a v of f and v is three times 10 to the eight meters per second.
02:56
And we just transformed the frequency to hearts...