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Hi there.
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So for this problem, we are asked for part a of this problem to calculate the wavelength of the 2p to 2s transition in lithium 3.
00:24
So to solve this, we know that from equation 10 .1, we will have that the energy, in this case is going to be the energy for the state to.
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2 times p minus the energy 2s.
00:41
So that will be minus 3 .5 minus 5 .5.
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Minus 5 .35.
00:51
Of course, these values are in electron bolts.
00:55
So from this, we obtain a value for the energy of 1 .85 electron volts.
01:05
Now we know that for photons, the wavelength in nanometers can be determined by 1 ,240 divided by the energy in electron bulbs.
01:21
So we will have that in this case is 1 .85.
01:25
So from this we obtain 670 .3 nanometers that we can express as 6 ,77 .7 that we can express as 6 ,7 .7 .3 nanometers that we can express as 6 ,7 ,000.
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103 amstroms.
01:41
So that's a solution for part a of this problem...