00:02
For part a, first we know that once the object is dropped, it is in free fall.
00:05
So we can take down as the negative y direction, and we can say the positive distance d from the lower dot to the mark corresponding to a certain reaction time t, this would be given by delta y, equalling negative d.
00:23
And this would be equalling negative 1 half gt squared, which in this case, d would then be equalling to gt squared over 2.
00:35
So we can say that for t sub 1, equaling 50 milliseconds.
00:42
So we have a 50 millisecond reaction time.
00:44
D sub 1, which should be equalling, 9 .8 meters per second squared, multiplied by 50 .0 times 10, to the negative third seconds quantity squared divided by 2 and this is giving us 0 .0123 meters or we can simply say 1 .23 centimeters.
01:12
For part b now we have d sub 2 equaling 100 milliseconds.
01:19
So for 100 milliseconds well we're simply doubling the time the reaction time and we know that this distance d is directly proportional to the time squared.
01:33
So we can simply say that this would be equaling d sub 2 would be equaling 4 times d sub 1 given that t sub 2 is equaling 2 times t sub 1.
01:48
This would equal approximately 4 .92 meters, or 4 .92 centimeters rather.
02:03
For part c then, we have t sub 3 equaling 150 milliseconds, which is three times the three times t sub 1.
02:20
And again, the distance is directly proportional to the time squared...