00:01
As per given question, we are provided with the values of molar mass of helium, that is mhe, is equal to 4 gram per mole.
00:10
And temperature is, that is temperature for helium is 300 kelvin.
00:18
And the molar mass, that is m .o2 for oxygen, is 32 gram per mole.
00:26
Now, first of all, we have divided the question into three parts.
00:30
First we have to calculate the average speed.
00:34
Average speed that is vav can be given as 3rt over m.
00:40
For helium it would become 3rt of helium and m of helium.
00:48
Now as per the given question, the average speeds are equal therefore 3rt of oxygen over molar mass of oxygen.
01:00
Here we get temperature of oxygen would equal to temperature of helium into molar mass of oxygen divided by molar mass of helium.
01:13
By substituting the values, we get the result as temperature of oxygen would be equal to 300 into 32 over 4...