00:01
In this question, we'll need to make use of the clausius -clapiron equation.
00:06
Lon over p1 over p2 is equal to delta h vapor pressure over r, 1 over t2, minus 1 over t1.
00:22
Now let's solve for the boiling point of water at the top of mount everest.
00:36
So we know that the pressure at the top of mount everest will hold that p1.
00:43
It's 244 millimeters of mercury, and we'll do this at the standard pressure, 760 millimeters of mercury.
00:58
And the enthalpy of vaporization is 40 .65 kilojoules per mole over.
01:10
Constant 8 .314 joules of a mole boiling point 373 kelvin standard pressure t1 here is our unknown solving here t1 is the boiling point of water at the top of mount debrose works out to 343 .28 kelvin so here are boiling point and now we'll solve for the freezing point of water the delta h vaporization would be for the boiling point.
01:49
So for the freezing point, it would be lon p1 over p2 is equal to the empty of fusion over r1 over t1.
02:05
And so the freezing point, mount everest, it would be lon 244 millimeters of mercury, over 760 millimeters mercury, mercury...