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A bacteria population starts with 400 bacteria and grows at a rate of $r(t)=(450.268) e^{1.12567 t}$ bacteria per hour. How many bacteria will there be after three hours?
11713 bacteria
Calculus 1 / AB
Calculus 2 / BC
Chapter 5
Integrals
Section 4
The Substitution Rule
Integration Techniques
Oregon State University
Baylor University
University of Michigan - Ann Arbor
Idaho State University
Lectures
01:11
In mathematics, integratio…
06:55
In grammar, determiners ar…
01:53
A bacteria population star…
0:00
03:41
Suppose that at time $t=0$…
01:40
The number of bacteria, $N…
A bacteria population is 4…
04:16
Growth of bacteria A colon…
03:33
A bacteria culture starts …
09:43
01:32
The number of bacteria …
01:18
03:51
Bacteria Growth A colony o…
02:44
Bacteria culture A culture…
02:56
Decrease in Bacteria When …
04:49
04:20
Growth of Bacteria The num…
07:00
00:56
Bacteria population If a b…
04:10
A bacteria culture initial…
06:14
we know that the rates are if he is simply the number of bacteria per unit at Time T used the equation. D B E T is equal to 4 50.26 82 The power for one times you can get D of T is equal to 450 0.268 point 268 e to the power off 1.12567 t divided by 1.12567 in order for self receiving plug in our initial condition, the coefficient should be equal to the initial population of 200. So we get C is equal to zero. So our final answer is falling for the population of easy. With three, we end up with 400 each of the power of 1.1225 times three, which is equal to 11713.23
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