Question
A bag of sand of mass $m$ is suspended by a rope. $A$ bullet of mass $\frac{m}{20}$ is fired at it with a velocity $v$ and gets embedded into it. The velocity of the bag finally is(a) $\frac{v}{20} \times 21$(b) $\frac{20 \mathrm{v}}{21}$(c) $\frac{v}{20}$(d) $\frac{v}{21}$
Step 1
Before the collision, the bullet has a momentum of $\frac{m}{20}v$ (mass times velocity), and the bag has a momentum of $0$ (since it is stationary). Show more…
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