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A ball is dropped from a height of 1.50 $\mathrm{m}$ and rebounds to a height of 1.20 $\mathrm{m} .$ Approximately how many rebounds will the ball make before losing 90$\%$ of its energy?

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11 bounces

Physics 101 Mechanics

Chapter 9

Linear Momentum

Motion Along a Straight Line

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

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Okay, So ordering Chapter nine. Probably seven. So says the balls dropped from a height 1.5 years and it rebounds to a high of 1.2 meters. Approximately how many rebounds with a ball make before losing 90% off its energy. Okay, so let's see how much interview one rebound takes, because we would assume that each bounce rule take him out the same proportion of the energy away. Right? So the amount of energy so he lost her bounds should be given as d k after the bounds over the cave before. Okay, well, the K before the bounds, it's gonna equal to potential at height before the bouts and the K after the bounce is gonna be the potential at the height after. So you have this. So this is now n g h. Time over in G H or 1.2 of the 1.5. This is your opponent. So this says 80% of the interviewee of loss after each bounce, that's actually wrong. Sorry. 80% is left after each bounce. Okay, so how many bounces before we lose 90% of the energy, So if we lose 90%. The energy that is having 10% left. So how many bounds Haven't it says this is right here saying, how many bounces in or after in bounces? This will be a 0.1. So how do we solve this equation? Well, we take the longer both sides. So in now it is logged 0.1 over ball of 0.8. We get in of 10 point, so obviously you can't have a 0.3 of the bounce, So that means after 11 bounces those over 90% of its energy, okay?

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