Question
A ball is thrown into the air from an initial height of $3 \mathrm{~m}$ with an initial velocity of $50 \mathrm{~m} / \mathrm{s}$. What is the position and velocity of the ball after $3 \mathrm{~s}$ ?
Step 1
First, we need to find the position of the ball after 3 seconds. We can use the equation for the position of an object under constant acceleration (in this case, gravity): y(t) = y0 + v0*t + 0.5*a*t^2 where y(t) is the position at time t, y0 is the Show more…
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