00:01
A ball is thrown upward from a height of 1 .5 meters at an initial speed of 40 meters per second.
00:06
Acceleration due to gravity is negative 9 .8 meters per square second.
00:09
Solve for the velocity, v of t, and height, h of t, of the ball t seconds after it is thrown and before it returns to the ground.
00:21
So the velocity of a function is equal to the integral of the acceleration of an object.
00:34
So the velocity would then be the integral, and we know the acceleration is given to be negative 9 .8, it's a constant, and then we just want to integrate with respect to t.
00:49
So the integral of negative 9 .8 would just be negative 9 .8 t, and then we have to add our constant plus c.
01:01
So we can actually find that plus c given the information of, we have the initial speed of 40 meters per second.
01:06
So we know that the initial speed, or v of zero, is 40 meters per second.
01:13
So if we do v of zero, which would be negative 9 .8 times zero plus c, we know that has to be 40.
01:25
So this would just be zero plus c equals 40.
01:29
That shows that our c has to be 40.
01:31
So that gives our velocity function, v of t, must be negative 9 .8 t plus 40...