a-ball-of-mass-05-mathrmkg-initially-at-rest-acquires-a-speed-of-4-mathrmm-mathrms-immediately-after

Question

A ball of mass 0.5 $\mathrm{kg}$ , initially at rest, acquires a speed of 4 $\mathrm{m} / \mathrm{s}$ immediately after being kicked by a force of strength 20 $\mathrm{N} .$ For how long did this force act on the ball?
(A) 0.01 $\mathrm{s}$
(B) 0.1 $\mathrm{s}$
(C) 0.2 $\mathrm{s}$
(D) 1 $\mathrm{s}$

Khoobchandra Agrawal · Accepted Answer

have all of mass 15 kg. Initially at rest, it&#x27;s kept by the force of continued and to a quarter final velocity of four m per second for how long the force is applied. Change of momentum of the world is called to product of force and time, so time will be changing momentum upon applied force. Final momentum minus initial momentum upon force Finding momentum, I&#x27;m into final diversity initially zero no substitute the value masses 15 His speed is four upon force that is continue to do so. It will be a point of 12 seconds, so answer you will get that is to be correct.

Matt Dransfield · Answer

Okay, This problem says as you catch a 0.14 kilogram ball, it accelerates at negative 320 meters per second squared and comes to rest in your hand. What forced is the ball exert on your hand? So physics Newtons per physics problems always are easier if you draw out or picture the problem. So here we have a ball with a mass of 0.14 kilograms, with a downward acceleration of negative 320 meters per second squared. Newton&#x27;s first law says force equals mass times acceleration, and so we can just use that formula to solve for force that the ball would act on your hand with. We&#x27;ll plug in what we know. We know that the masses 0.14 kilo grams put that in some parentheses who fixed my G there and then the acceleration, his negative 300 20 meters per second squared. And when you do the math, you&#x27;ll find that the force that the ball is pushing down on your hand is negative. 45 new tens, and so to stop the ball, your hand would have to supply positive 45 new tens. So that&#x27;s how you solve

Sheh Lit Chang · Answer

in this question, we have a bar. Are that jobs particularly onto a floor? Okay. Because speed of $25 for a second. And then after every bounce Elusive speed off 10 m/s, The mess of the bar. Yes, 1.2 Kids. You you want to find out. Oh, Impulse and many two of the average force on the floor. So I&#x27;m going to take uh the upward direction to be positive direction. Okay, So to find the impulse on the ball will be finding a change in momentum at the ball. Okay, So because the definition of impulses uh delta P, which is P. F minus P. I. Okay, so the initial momentum. Yes, 1.2 times 25. And then in the minus jihad direction. So this is my nurse. 30 jihad. Did you read us a second and then the final momentum? Okay. It is 1.2 times 10 times. Ah Jihad. Okay, so this is Charles your heads. Kg. He does. It&#x27;s OK. Okay. Yeah, Record that. The momentum is mass times velocity and then the impulse is equal to that happy. So um I know momentum. My notice initial momentum. So we have 12 -330 jihad. Okay, so we have 42. You had a G meters a second. Okay, so if you are interested in the 92 of the impulse, yes. 42 kg media is called a second. Okay, so this is the answer for parquet. And then probably you are interested in finding that many tube of the average falls on the floor, right? A ball? Okay, So it&#x27;s actually the same thing as um I think uh which force on the no is equal to the average force on the bone. Uh huh. In many to This is uh in 92. Okay, and this is Newton&#x27;s 3rd law. So um so the magnitude of the average force is equal to that happy. You&#x27;re right by delta T uh we&#x27;ll do this. So we have 42 b. bye bye. 0.02. And you get 2100 good things. So this is the answer for happy, and that&#x27;s all for this question.

Mayukh Banik · Answer

So here we&#x27;re trying to draw our force worse this time. So the vertical axis is force in terms off, new done and the rise of the accidents time in in seconds in zero point doubles, it&#x27;ll one second it goes from then your deed goes from zero to take the four Newton and then batted down in same amount of time. So which means it goes like this on this is zero porn double zero to seconds. Now the average force acting on the body is so average foresees integration of force with DB divided by that total time. So that will be given by the area under the force time golf Divided by total time, which is half times base, he&#x27;s 0.2 seconds time the Heidi&#x27;s 10 to the four new done divided by 0.2 2nd So that comes out to be 5000 nude. Um, we will use fourth equals masters accidentally should to find the acceleration to be force over mass. It was 5000 new done, delighted by the report 145 kilogram, and that comes out to be 34 for a B three meter per second squared the final velocity of the ball with the given by the final. It was reinitiated with zero tow US acceleration times time So 34 for 83 mater by second square times syrup or 002 made the seconds so that comes out to be 68.96 meter per second or approximately equals 2 69 meters per second. Now, initially it was at zero. So assuming it reverses direction, the, uh, final velocity after this entire time. So after t equals 0.2 2nd will be 69 meters per second divide by two. It was 35 meters for a second.

Matt Dransfield · Answer

all right. So a 0.53 kilogram billiard ball, initially at rest was given a speed of 12 meters per second during a time interval. The four milliseconds. What average force acted on the ball during this time? So too solve this problem right out your knowns. 0.53 kilogram billiard ball. Initial velocity, zero meters per second. Final velocity. 12 meters per second on a time interval of 4.0 milliseconds. In order to deal with this, you need the units and standard form. So convert this two seconds. You have 4.0 times 10 to the negative third seconds. And in order to calculate the force, you&#x27;ll first need to calculate the acceleration. And this is because we know from Newton&#x27;s laws force equals mass times acceleration. We know the mass. We do not know the acceleration. We can use the equation. Acceleration equals the change in velocity over the change in time. Since we know these two variables, we can substitute this term changing V over changing T for a In this equation, giving us force equals mass times change in velocity over change in time. Now we can substitute in what we know here. We know the mass is zero point five three kilograms. It&#x27;s the mass and we know the change in velocity. It goes from 0 to 12 meters per second. That&#x27;s our change in mass, and our change in time is 4.0 times 10 to the negative three seconds. And that&#x27;s really important because the second&#x27;s need to ah, both beyond the denominator to make this an acceleration. See why changing the units is important here from milliseconds two seconds. Then we do out the math to get our overall force. And when you run the numbers 3.53 times 12 divided by this term, you end up with 1600 mu tins. And then we can turn that into Kilo. Newton&#x27;s 1.6 kilo new tens that&#x27;s just dividing by 1000 to switch from base unit two Kilogram Newtons Kilo Newton&#x27;s que O Gram Q. So that&#x27;s how I would solve that problem.

Manish Kumar · Answer

because you have to use your impulse from life. You know that it was nothing but after Delta D. That is nothing. But I am into changing moment of that Jamie to be paramount being issued. That is Delta P. So basically, we can find posed by the this corner that Delta be upon Delta T which makes it mass over there and that each given Invisibles too, did a point five g and B final over there that picture it major part second and initially obviously zero on the time over there that it&#x27;s 0.25 So the fourth over there, that basically comes out 17.6 new done.

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