00:03
In this problem, we have a ball that is being thrown horizontally at a speed of 23 .7 meters per second.
00:18
And this ball will go and land approximately 31 meters from the building.
00:28
And we want to know, well, how high is this building? this is a projectile, so we need to separate our information in its horizontal and vertical components.
00:38
Since it is moving horizontally at first, all that velocity is in the horizontal direction, and therefore the initial velocity in the y or vertical will be zero.
00:50
This distance that lands away is the horizontal distance, and we know there is acceleration in the y direction, which is the acceleration due to gravity.
01:03
And we're trying to figure out the vertical distance.
01:07
To do this, we're going to need time.
01:10
But we don't have time.
01:12
Over time is the same in both the horizontal and vertical sides of projectile motion.
01:18
And so we can use our horizontal equation, which is simply velocity equals distance over time.
01:25
If we were to rearrange this for time, it would be distance divided by velocity, which would be 31 divided by 23 .7.
01:36
And from that, we get a time of approximately 1 .3 seconds...