00:01
For this problem, we are told that a ballast is dropped from a stationary hot air balloon that is hovering at an altitude of 400 feet.
00:08
The velocity of the ballast after t seconds is negative 32t plus 4 feet per second.
00:13
For part a, we're asked to find the height h of t of the ballast from the ground at time t.
00:18
So, h of t is going to be antiderivative of the velocity of its fall.
00:23
So the antiderivative of negative 32t is going to be negative 32t squared over 2, and that is going to give us negative 16 t squared, then plus the antiderivative of 4 is going to be 4t.
00:39
Then we need to add on our constant.
00:43
Now we know that our height at time zero is going to be 400 feet, which means that c must then equal 400.
00:52
So we can say for part a, the answer is h of t equals negative 16 t squared, plus 4t plus 400.
01:02
Now for part b, we are asked, when will the ballast hit the ground? so that is just going to be a matter of solving the quadratic equation, negative 16 squared plus 4t plus 400.
01:16
Now we can do that as t equals negative 4 plus or minus the square root of 4 squared, so that's 16 minus 4 ac, so 16 minus 4 times negative 16 times 400, all divided by 2 times a.
01:37
So all divided by negative 32.
01:40
I'm going to pause and calculate that off screen...