Question
A balloon does 324 J of work on the surroundings as it expands under a constant pressure of $7.33 \times 10^{4} \mathrm{Pa}$. What is the change in volume (in L) of the balloon?
Step 1
33 \times 10^{4} \mathrm{Pa}$. We need to find the change in volume. The formula for work done is $W = -P \Delta V$, where $P$ is the pressure and $\Delta V$ is the change in volume. Show more…
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