Question
A balloon expands from 0.75 L. to 1.20 L.as it is heated under a constant pressure of $1.01 \times 10^{5} \mathrm{Pa}$. Calculate the work (in J) done by the balloon on the environment.
Step 1
We know that 1 Pascal is equal to $1 \times 10^{-5}$ bar. So, the pressure in bar is: \[P = 1.01 \times 10^{5} \times 1 \times 10^{-5} = 1.01 \, \text{bar}\] Show more…
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