00:01
First of all, to calculate heat q, so that will be given by that is a relation n, multiplied by c multiplied by delta t.
00:13
So here n is the number of moles of gas c.
00:17
Is the more heat capacity delta t? is the temperature change and q is the heat supplied? so this can also be written as q is equals to n multiplied by c multiplied by t 2 minus t 1- that is final temperature minus initial temperature.
00:38
So now our q is equals to so that is 39.1 mole, multiplied by specific, that is molar heat capacity.
01:01
So molar heat capacity is given to us that is 20.8 joule per degree celsius per mole, multiplying final temperature, that is 38.0 degree celsius, minus 0 degree celsius.
01:21
So solving this or qisequals to this will be 30904.64 and solving the unit.
01:35
This will be joule or, if i want to convert it into kilo joules.
01:39
So we know that since 1 kilo joule, so that will be equal to 1000 joules.
01:50
So this will be divided by 1000 and q equals to 30.904 kilo joules.
02:02
So that is the heat required now we have next part for work, done, work done w, so that's equal to p delta v...