00:02
So we have an objective function of z equals 28x plus 52y, where x is equal to the number of six -person rectangular tables and y is equal to the number of 10 -person round tables.
00:16
Z is the cost of both these tables together.
00:20
See, 28 is the cost per six -person table, and $52 is the cost per 10 -person round table.
00:28
So in order to minimize z, we are subject to the following constraints.
00:33
X and y both have to be greater than or equal to zero.
00:37
And then 6x plus 10y, these are the seatings per table, must be equal to 250 because we need to be able to seat 250 people according to the problem.
00:52
Also, the hall where this is happening, where we will be putting the tables, has a maximum of 35 tables that can be in it.
01:00
So x plus y must be smaller than or equal to 35.
01:06
Finally, we only have 15 of the six person rectangular tables.
01:11
So x has to be smaller than or equal to 15.
01:16
So i've graphed this out on the right...