A bar magnet $20 \mathrm{~cm}$ in length is placed with its south pole towards geographie north. 'The neutral points are situated at a distance of $40 \mathrm{~cm}$ from centre of the magnet. If horizontal component of earth's field $3.2 \times 10^{-5} \mathrm{~T}$, then pole strength of magnet is
(a) $5 \mathrm{Am}$
(b) $10 \mathrm{Am}$
(c) $45 \mathrm{Am}$
(d) 20 Am