00:01
Show that the energy of a dipole in the magnetic field b is given by u equals to minus m dot b for b part show that the interaction energy of two magnetic dipoles magnetic diapoles separated by the displacement r is given by u equals 1 nu not by 4 pi 1 by r cubed m1 .m2 minus 3m1 .r.
00:45
Rcaf m2 dot rcap m2 dot rcap.
00:50
Third part is express your answer to be in terms of angle theta 1 and theta 2 and use the result to find the stable configuration two diapoles would adopt.
01:04
And the part is suppose you had a large collection of compass needles mounted on the pins at regular intervals along a straight line, how would they point, assuming the earth's magnetic field can be neglected? the magnetic field is a vector and the direction of the magnetic field is from north pole to south.
01:33
The magnetic dipole is a combination of north and south pole separated by a small distance up.
01:43
If the dipole is placed in a uniform magnetic field, the south pole of dipole turns opposite to the field, opposite to field and the north of dipole is in the direction of field.
02:01
In field, the force experienced by both the poles equal, which constitutes the torque, the torque rotates the dipole, the dipole, made to align in the field direction of the magnetic field.
02:28
Hence the construction and magnetic dipole shows the direction of the magnetic field.
02:33
For first part, the torque n on the dipole of diapol moment m in the magnetic field b makes an angle of theta.
02:45
So the torque is given by m b sine theta.
02:48
The work done in rotating the dipole through a small angle d theta, then dw is tau d theta, which can be written as mb sine theta, d theta.
03:05
The total work done in rotating the diapol from its initial position, theta 1 to theta 2 is given by w.
03:18
Integration from theta 1 to theta 2 mb sine theta d theta which will be equals to mb cos theta 1 minus cos theta 2 if u theta 1 and u theta 2 be the potential energies potential energies of the dipole at position theta 1 and theta 2, then this work done accounts for the change in potential energy of the diapoline rotating it from theta 1 to theta 2.
04:01
So the work done w is given by u theta 2 minus u theta 1 which is equal to minus of mb cause theta 2 minus cos theta 1 which can also be written as minus of m dot b.
04:24
From this we can conclude that the potential energy of a dipole at position theta is minus m .b.
04:32
The diagram following shows two magnetic dipole separated by a distance are the diagram is shown...