00:01
Consider two metal bars of the same length and cross -sectional area, but one is made of gold and one is made of silver, that are in formal contact with each other and insulated on the sides.
00:11
The end of the gold bar is maintained at a temperature t .s.
00:15
Hot of 80 .0 degrees celsius, while the silver bar is maintained at a temperature t's of cold of 30 .0 degrees celsius.
00:25
And we want to know what is the temperature at the junction point.
00:30
T sub j and we're going to do this using just the law of formal radiation which tells us that the power is given by the thermal conductivity k times the cross -sectional area a which again is the same for both of our bars and then just the temperature gradient d t over d x and for us for these bars, this temperature gradient is just going to be the hot temperature minus the cold temperature of each individual bar over their length, which again is the same length for both bars.
01:12
So let's go ahead and write these power equations for each bar.
01:16
So our power for gold is o.
01:19
But first we're going to need to figure out what these caves are.
01:22
So let's go into table 20 .3, which will give us our thermal conductivities, and our kappa her goal is going to be 314, and these come in watts per meter degree celsius, and our k4 silver, is going to be 427 watts.
01:52
Per meter degree celsius.
01:55
So let's go ahead and write these.
01:58
So our for gold, this is going to be again, that 314 watts per meter degree celsius, our thermal conductivity.
02:08
We can go ahead and pull out these constants between both of them, the a and the l.
02:15
And put that right here as an a over l.
02:20
And those units are meters squared over meters.
02:25
So this is just in meters.
02:27
And finally, just the change in temperatures.
02:31
So for our block of gold, we're going from this temperature hot to the junction point...