00:01
So for part a, we want the damping constant.
00:05
So we need to apply newton's second law to the bar when it is at a distance x beyond the equilibrium position and released.
00:17
So that would be the equation b equals bl squared divided by r.
00:25
If you plug in what you know to the equation, 1 .00 ts times 0 .400 meters.
00:36
Divided by 0 .500, you get 0 .320 kilograms per second.
00:49
For part b, we want the frequency.
00:52
For dampen harmonic motion, we have f prime is equal to w prime over 2 pi, which is equal to 1 over 2 pi times the square root of k divided by m minus b squared over 4m squared.
01:11
So if we put in the values we get f prime is equal to 1 .38 hertz.
01:22
For part c, we want the amplitude at t equals 5 seconds.
01:27
So that would be a of t equals a, knot, e to the negative b divided by 2m times t...