00:01
Hello and welcome to this video solution of numerate.
00:04
So here we are given the figure that shows the plot of velocity for a car traveling in a straight line.
00:11
Right.
00:12
So this is in meters per second which is a vertical axis and the time is in seconds.
00:17
Now, now a you have to calculate the average velocity between t equal to 6 and t equal to 11 seconds.
00:24
So 6 is here and 11 is here.
00:26
Right.
00:27
So average velocity a v will be equal to the change in velocity over the change in time.
00:35
Right.
00:35
So change in velocity will be at the final point it's 14 initial point it's 4 and the change in time is 11 minus 6.
00:45
Right.
00:46
So it's 10 by 5.
00:47
So it's 2 meters per second where is the value of the acceleration.
00:53
B is what is the average velocity for the same time interval.
01:01
Now to calculate the velocity you need to calculate the distance.
01:07
Right.
01:07
Covered in this time interval.
01:10
I have by this can be calculated by taking the area under the curve.
01:14
So s will be equal to if you just compute the area then this consists of this below rectangle which is 4 times of 5.
01:26
Right.
01:27
And the above triangle is half times the base is 5 times altitude is 10.
01:32
Right.
01:33
So this is a total area you will be having.
01:35
So it's 20 plus 25.
01:40
So it's 45 meters is the displacement.
01:45
So the average velocity will be equal to the displacement over time...