Question
A baseball is popped straight up with an initial velocity of $25 \mathrm{m} / \mathrm{s}$. The baseball has a diameter of $0.073 \mathrm{m}$ and a mass of $0.143 \mathrm{kg} .$ The drag coefficient for the baseball can be estimated as 0.47 for $R e<10^{4}$ and 0.10 for $R e>10^{4}$ Determine how long the ball will be in the air and how high it will go.
Step 1
The drag force on the baseball is given by $F_D = \frac{1}{2} \rho A v^2 C_D$, where $\rho$ is the air density, $A$ is the cross-sectional area of the baseball, $v$ is the velocity of the baseball, and $C_D$ is the drag coefficient. Show more…
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A baseball, with $m=145 \mathrm{g}$, is thrown directly upward from the initial position $z=0$ and $V_{0}=45 \mathrm{m} / \mathrm{s}$. The air drag on the ball is $C V^{2}$, as in Prob. 1.19 , where $C \approx 0.0013 \mathrm{N}$ $\mathrm{s}^{2} / \mathrm{m}^{2} .$ Set up a differential equation for the ball motion, and solve for the instantaneous velocity $V(t)$ and position $z(t)$ Find the maximum height $z_{\max }$ reached by the ball, and compare your results with the classical case of zero air drag.
A $0.142-\mathrm{kg}$ baseball has a terminal speed of $42.5 \mathrm{~m} / \mathrm{s}$ $(95 \mathrm{mi} / \mathrm{h})$. (a) If a baseball experiences a drag force of magnitude $R=C v^{2}$, what is the value of the constant $C$ ? (b) What is the magnitude of the drag force when the speed of the baseball is $86.0 \mathrm{~m} / \mathrm{s} ?$ (c) Use a computer to determine the motion of a baseball thrown vertically upward at an initial speed of $36.0 \mathrm{~m} / \mathrm{s}$. What maximum height does the ball reach? How long is it in the air? What is its speed just before it hits the ground?
(II) A baseball is hit almost straight up into the air with a speed of 25 m/s. Estimate ($a$) how high it goes, ($b$) how long it is in the air. ($c$) What factors make this an estimate?
DESCRIBING MOTION: KINEMATICS IN ONE DIMENSION
Freely Falling Objects
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